physics : class12 Mass Defect Calculation : Mass Defect : Atoms and Nuclei MCQ Questions and Answers
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Mass Defect Calculation
MCQ questions and answers.
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MCQ Questions
1. The total mass of the separate proton and neutron in a deuterium nucleus is 2.0160 u, while the actual mass of the nucleus is 2.0136 u. What is the mass defect?
A.
0.0012 u
B.
0.0024 u
C.
0.0048 u
D.
2.0148 u
Correct Answer:
0.0024 u
Explanation:
Mass defect = mass of separate nucleons − actual nuclear mass = 2.0160 u − 2.0136 u = 0.0024 u.
2. For a helium-4 nucleus, the total mass of two free protons and two free neutrons is 4.0320 u. If the actual nuclear mass is 4.0015 u, what is the mass defect?
A.
0.01525 u
B.
0.0305 u
C.
0.0315 u
D.
4.01675 u
Correct Answer:
0.0305 u
Explanation:
Mass defect = 4.0320 u − 4.0015 u = 0.0305 u.
3. The masses of three separate nucleons are 1.008 u, 1.009 u, and 1.007 u. If their combined nuclear mass is 3.021 u, what is the mass defect?
A.
0.001 u
B.
0.002 u
C.
0.003 u
D.
3.024 u
Correct Answer:
0.003 u
Explanation:
The sum of the separate nucleon masses is 1.008 u + 1.009 u + 1.007 u = 3.024 u. Therefore, mass defect = 3.024 u − 3.021 u = 0.003 u.
4. Using atomic masses, the mass of two hydrogen atoms and two neutrons is 4.0330 u, while the mass of a helium atom is 4.0026 u. What is the mass defect of helium-4?
A.
0.0204 u
B.
0.0304 u
C.
0.0314 u
D.
4.0178 u
Correct Answer:
0.0304 u
Explanation:
Mass defect = mass of constituent atoms and neutrons − mass of helium atom = 4.0330 u − 4.0026 u = 0.0304 u.
5. The total mass of the separate nucleons of a nucleus is 10.080 u, and the actual mass of the nucleus is 10.050 u. What is the mass defect?
A.
0.003 u
B.
0.030 u
C.
0.300 u
D.
20.130 u
Correct Answer:
0.030 u
Explanation:
Mass defect is found by subtracting the actual nuclear mass from the total mass of the separate nucleons: 10.080 u − 10.050 u = 0.030 u.
6. A nucleus has a mass defect of 0.005 u. If the total mass of its separate nucleons is 12.010 u, what is the actual mass of the nucleus?
A.
12.005 u
B.
12.015 u
C.
0.005 u
D.
12.000 u
Correct Answer:
12.005 u
Explanation:
Actual nuclear mass = total mass of separate nucleons − mass defect = 12.010 u − 0.005 u = 12.005 u.
7. The separate nucleons of a nucleus have a total mass of 6.048 u, while the actual nuclear mass is 6.042 u. Express the mass defect in kilograms. Use 1 u = 1.66 × 10^-27 kg.
A.
9.96 × 10^-30 kg
B.
3.60 × 10^-29 kg
C.
9.96 × 10^-27 kg
D.
1.66 × 10^-29 kg
Correct Answer:
9.96 × 10^-30 kg
Explanation:
Mass defect = 6.048 u − 6.042 u = 0.006 u. In kilograms, 0.006 × 1.66 × 10^-27 kg = 9.96 × 10^-30 kg.
8. The masses of two protons and one neutron are 2.0146 u and 1.0087 u, respectively. If the mass of the nucleus is 3.0203 u, what is its mass defect?
A.
0.0010 u
B.
0.0020 u
C.
0.0030 u
D.
3.0233 u
Correct Answer:
0.0030 u
Explanation:
Total mass of separate nucleons = 2.0146 u + 1.0087 u = 3.0233 u. Mass defect = 3.0233 u − 3.0203 u = 0.0030 u.
9. A nucleus contains four nucleons, each having a mass of 1.008 u when separate. If the actual nuclear mass is 4.024 u, what is the mass defect?
A.
0.008 u
B.
0.016 u
C.
0.032 u
D.
4.032 u
Correct Answer:
0.008 u
Explanation:
Total mass of separate nucleons = 4 × 1.008 u = 4.032 u. Hence, mass defect = 4.032 u − 4.024 u = 0.008 u.
10. The mass defect of a nucleus is 0.012 u. If the actual nuclear mass is 15.988 u, what is the total mass of its separate nucleons?
A.
15.976 u
B.
15.988 u
C.
16.000 u
D.
16.012 u
Correct Answer:
16.000 u
Explanation:
Mass defect = total mass of separate nucleons − actual nuclear mass. Therefore, total mass of separate nucleons = 0.012 u + 15.988 u = 16.000 u.
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