physics : class11 Angle of Projection : Projectile Motion : Kinematics MCQ Questions and Answers
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Angle of Projection
MCQ questions and answers.
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MCQ Questions
1. At what angle of projection does a projectile attain its maximum horizontal range on level ground?
A.
30°
B.
45°
C.
60°
D.
90°
Correct Answer:
45°
Explanation:
For a given initial speed and equal launch and landing levels, the horizontal range is maximum when the angle of projection is 45°.
2. A projectile is thrown at an angle of 0° to the horizontal. In which direction is its initial velocity?
A.
Vertically upward
B.
Vertically downward
C.
Horizontally
D.
At 45° to the horizontal
Correct Answer:
Horizontally
Explanation:
An angle of projection of 0° means that the projectile is launched entirely along the horizontal direction.
3. At what angle of projection is the vertical component of the initial velocity maximum for a fixed initial speed?
A.
0°
B.
30°
C.
45°
D.
90°
Correct Answer:
90°
Explanation:
The vertical component is u sin θ. For a fixed speed u, sin θ is maximum at θ = 90°.
4. At what angle of projection is the horizontal component of the initial velocity maximum for a fixed initial speed?
A.
0°
B.
30°
C.
45°
D.
90°
Correct Answer:
0°
Explanation:
The horizontal component is u cos θ. For a fixed speed u, cos θ is maximum at θ = 0°.
5. Two projectiles are projected with the same speed at angles 30° and 60° on level ground. How are their horizontal ranges related?
A.
The range at 30° is greater
B.
The range at 60° is greater
C.
Both ranges are equal
D.
Both ranges are zero
Correct Answer:
Both ranges are equal
Explanation:
Complementary angles, such as 30° and 60°, give the same range because sin(2 × 30°) equals sin(2 × 60°).
6. Which pair of angles of projection gives the same horizontal range for the same initial speed on level ground?
A.
20° and 40°
B.
25° and 65°
C.
30° and 50°
D.
40° and 60°
Correct Answer:
25° and 65°
Explanation:
Two complementary angles produce the same range. Since 25° + 65° = 90°, this pair gives equal horizontal ranges.
7. If a projectile is projected with speed u at an angle θ to the horizontal, what is its initial vertical component of velocity?
A.
u cos θ
B.
u sin θ
C.
u tan θ
D.
u
Correct Answer:
u sin θ
Explanation:
Resolving the initial velocity into components, the vertical component is u sin θ when θ is measured from the horizontal.
8. If a projectile is projected with speed u at an angle θ to the horizontal, what is its initial horizontal component of velocity?
A.
u sin θ
B.
u cos θ
C.
u tan θ
D.
u divided by sin θ
Correct Answer:
u cos θ
Explanation:
Resolving the initial velocity into components, the horizontal component is u cos θ when θ is measured from the horizontal.
9. For a projectile projected with a fixed speed on level ground, which angle gives the greatest height?
A.
0°
B.
30°
C.
45°
D.
90°
Correct Answer:
90°
Explanation:
The maximum height depends on the square of the vertical component, u sin θ. This component is greatest at 90°.
10. A projectile is projected at an angle of 45° to the horizontal. What is the relation between its initial horizontal and vertical velocity components?
A.
The horizontal component is twice the vertical component
B.
The vertical component is twice the horizontal component
C.
Both components are equal
D.
The horizontal component is zero
Correct Answer:
Both components are equal
Explanation:
At 45°, the components are u cos 45° and u sin 45°. Since sin 45° equals cos 45°, the two components are equal.