physics : class11 Angle of Projection : Projectile Motion : Kinematics MCQ Questions and Answers
Practice important
Angle of Projection
MCQ questions and answers.
Page 2
of
2
|
20
MCQ Questions
1. A projectile is launched with speed u at an angle θ above the horizontal. What is its initial horizontal velocity component?
A.
u sin θ
B.
u cos θ
C.
u tan θ
D.
u divided by cos θ
Correct Answer:
u cos θ
Explanation:
The velocity vector makes an angle θ with the horizontal, so its horizontal component is u cos θ.
2. A projectile is launched with speed u at an angle θ above the horizontal. What is its initial vertical velocity component?
A.
u cos θ
B.
u tan θ
C.
u sin θ
D.
u divided by sin θ
Correct Answer:
u sin θ
Explanation:
The vertical component of the initial velocity is obtained by resolving u along the vertical direction, giving u sin θ.
3. For a projectile to have the maximum horizontal range on level ground, the angle of projection should be
A.
30°
B.
45°
C.
60°
D.
90°
Correct Answer:
45°
Explanation:
For a fixed initial speed and level ground, the horizontal range is maximum when the angle of projection is 45°.
4. Two projectiles are launched with the same speed at angles 30° and 60° on level ground. Their horizontal ranges are
A.
Greater for 30°
B.
Greater for 60°
C.
Equal
D.
Zero for both
Correct Answer:
Equal
Explanation:
Angles 30° and 60° are complementary, and complementary angles of projection give equal ranges when the launch speed and landing level are the same.
5. If a projectile is projected at an angle of 90° to the horizontal, its motion is
A.
Purely horizontal
B.
Purely vertical
C.
Along a direction at 45°
D.
Circular
Correct Answer:
Purely vertical
Explanation:
At an angle of 90°, the horizontal component of velocity is zero, so the projectile moves vertically upward and downward.
6. If the angle of projection is 0° above the horizontal, the initial vertical component of velocity is
A.
u
B.
u sin 45°
C.
Zero
D.
u cos 45°
Correct Answer:
Zero
Explanation:
The initial vertical component is u sin θ. For θ = 0°, u sin 0° equals zero.
7. For a projectile launched at an angle θ, which expression represents the ratio of its initial vertical component to its initial horizontal component?
A.
sin θ
B.
cos θ
C.
tan θ
D.
cot θ
Correct Answer:
tan θ
Explanation:
The ratio is (u sin θ) divided by (u cos θ), which simplifies to tan θ.
8. A projectile is launched with the same speed at angles 20° and 70°. Compared with the projectile launched at 20°, the projectile launched at 70° has
A.
The same horizontal range
B.
Twice the horizontal range
C.
Half the horizontal range
D.
Zero horizontal range
Correct Answer:
The same horizontal range
Explanation:
Since 20° and 70° are complementary angles, they produce the same horizontal range on level ground for the same initial speed.
9. For a projectile launched with a fixed speed, increasing the angle of projection from 0° toward 45° generally causes its horizontal range to
A.
Increase
B.
Decrease immediately
C.
Remain zero
D.
Become independent of the angle
Correct Answer:
Increase
Explanation:
The range increases as the angle rises from 0° to 45°, reaching its maximum value at 45°.
10. A projectile is launched at an angle θ and another at an angle (90° − θ), both with the same speed on level ground. Their ranges are
A.
Always different
B.
Equal
C.
Equal only when θ = 90°
D.
Zero for the second projectile
Correct Answer:
Equal
Explanation:
The two angles are complementary, and complementary angles of projection give equal horizontal ranges for the same initial speed.