biology : class12 Vector Insert Ratio : DNA Isolation, Restriction Enzymes, Vector, Ligation, Host Cell : Recombinant DNA Technology MCQ Questions and Answers
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Vector Insert Ratio
MCQ questions and answers.
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MCQ Questions
1. A 3,000 bp linearized vector is used at 50 ng in a ligation. How much mass of a 900 bp insert is required to obtain a 2:1 insert-to-vector molar ratio?
A.
15 ng
B.
30 ng
C.
45 ng
D.
60 ng
Correct Answer:
30 ng
Explanation:
Molar ratio = (insert mass/vector mass) × (vector length/insert length). Thus, 2 = (insert mass/50) × (3000/900), giving an insert mass of 30 ng.
2. A ligation contains 100 ng of a 4,000 bp vector and a 1,000 bp insert. What insert mass is needed for a 3:1 insert-to-vector molar ratio?
A.
50 ng
B.
75 ng
C.
100 ng
D.
125 ng
Correct Answer:
75 ng
Explanation:
Required insert mass = molar ratio × vector mass × insert length/vector length = 3 × 100 × 1000/4000 = 75 ng.
3. A 5,000 bp vector is used at 80 ng with 36 ng of a 750 bp insert. What is the insert-to-vector molar ratio?
A.
1:1
B.
2:1
C.
3:1
D.
4:1
Correct Answer:
3:1
Explanation:
The ratio is (36/80) × (5000/750) = 3. Therefore, the insert molecules are present at three times the number of vector molecules.
4. For a ligation using 100 ng of a 6,000 bp vector and a 1,500 bp insert, what insert mass produces a 4:1 insert-to-vector molar ratio?
A.
50 ng
B.
75 ng
C.
100 ng
D.
150 ng
Correct Answer:
100 ng
Explanation:
Insert mass = 4 × 100 ng × (1500/6000) = 100 ng. The shorter insert requires an equal mass here because it is one-fourth the vector length and is used at four times the molar amount.
5. A 5,000 bp vector is present at 20 ng/µL, and 5 µL is used. A 1,000 bp insert is available at 10 ng/µL. What volume of insert is required for a 2:1 insert-to-vector molar ratio?
A.
2 µL
B.
3 µL
C.
4 µL
D.
5 µL
Correct Answer:
4 µL
Explanation:
The vector mass is 20 × 5 = 100 ng. Required insert mass = 2 × 100 × (1000/5000) = 40 ng. At 10 ng/µL, the required volume is 40/10 = 4 µL.
6. A 4,000 bp vector and a 2,000 bp insert are used in a ligation. If 50 ng of vector and 30 ng of insert are added, what is the insert-to-vector molar ratio?
A.
0.3:1
B.
0.6:1
C.
1.2:1
D.
2.4:1
Correct Answer:
1.2:1
Explanation:
The molar ratio is (30/50) × (4000/2000) = 1.2. Thus, the insert is present at 1.2 times the molar amount of the vector.
7. Equal masses of a 2,000 bp vector and a 1,000 bp insert are used in a ligation. What is the resulting insert-to-vector molar ratio?
A.
0.5:1
B.
1:1
C.
2:1
D.
4:1
Correct Answer:
2:1
Explanation:
For equal DNA masses, the number of molecules is inversely proportional to fragment length. Since the insert is half the vector length, equal mass provides twice as many insert molecules, giving a 2:1 ratio.
8. A 7,200 bp vector is used at 40 ng, and a 1,800 bp insert is available at 20 ng/µL. What insert volume is needed for a 3:1 insert-to-vector molar ratio?
A.
1.0 µL
B.
1.5 µL
C.
2.0 µL
D.
3.0 µL
Correct Answer:
1.5 µL
Explanation:
Required insert mass = 3 × 40 × (1800/7200) = 30 ng. At 20 ng/µL, the required volume is 30/20 = 1.5 µL.
9. To achieve a 1:1 molar ratio, how much mass of a 1,200 bp insert should be combined with 80 ng of a 4,800 bp vector?
A.
10 ng
B.
20 ng
C.
40 ng
D.
60 ng
Correct Answer:
20 ng
Explanation:
For a 1:1 molar ratio, insert mass = vector mass × insert length/vector length = 80 × 1200/4800 = 20 ng.
10. A 2,500 bp vector is used at 60 ng. A 750 bp insert is available at 15 ng/µL. What volume of insert is required for a 4:1 insert-to-vector molar ratio?
A.
2.4 µL
B.
3.2 µL
C.
4.8 µL
D.
6.0 µL
Correct Answer:
4.8 µL
Explanation:
Required insert mass = 4 × 60 × (750/2500) = 72 ng. At 15 ng/µL, the required volume is 72/15 = 4.8 µL.
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