Phosphoenolpyruvate Formation MCQ Questions and Answers
1. Which compound is converted into phosphoenolpyruvate during glycolysis?
A. 3-phosphoglycerate
B. 2-phosphoglycerate
C. Pyruvate
D. Glyceraldehyde-3-phosphate
Correct Answer:
2-phosphoglycerate
Explanation:
During phosphoenolpyruvate formation, 2-phosphoglycerate is converted into phosphoenolpyruvate.
2. Which enzyme catalyzes the formation of phosphoenolpyruvate in glycolysis?
A. Phosphoglycerate kinase
B. Pyruvate kinase
C. Enolase
D. Hexokinase
Correct Answer:
Enolase
Explanation:
Enolase catalyzes the conversion of 2-phosphoglycerate into phosphoenolpyruvate.
3. What type of reaction forms phosphoenolpyruvate from 2-phosphoglycerate?
A. Hydrolysis
B. Dehydration
C. Phosphorylation
D. Oxidation
Correct Answer:
Dehydration
Explanation:
The formation of phosphoenolpyruvate involves removal of a water molecule from 2-phosphoglycerate, making it a dehydration reaction.
4. What molecule is released when 2-phosphoglycerate is converted to phosphoenolpyruvate?
A. Carbon dioxide
B. ATP
C. Water
D. NADH
Correct Answer:
Water
Explanation:
Enolase removes water from 2-phosphoglycerate during the formation of phosphoenolpyruvate.
5. Phosphoenolpyruvate is formed during which step of glycolysis?
A. Step 5
B. Step 7
C. Step 9
D. Step 10
Correct Answer:
Step 9
Explanation:
Phosphoenolpyruvate is produced in the ninth step of glycolysis when enolase acts on 2-phosphoglycerate.
6. Which statement correctly describes phosphoenolpyruvate formation?
A. 2-phosphoglycerate gains a phosphate group
B. 2-phosphoglycerate loses water
C. Pyruvate gains carbon dioxide
D. 3-phosphoglycerate loses ATP
Correct Answer:
2-phosphoglycerate loses water
Explanation:
Phosphoenolpyruvate formation occurs through dehydration of 2-phosphoglycerate.
7. What is the main product of the enolase-catalyzed reaction in glycolysis?
A. Phosphoenolpyruvate
B. 2-phosphoglycerate
C. 1,3-bisphosphoglycerate
D. Lactate
Correct Answer:
Phosphoenolpyruvate
Explanation:
The enolase reaction produces phosphoenolpyruvate from 2-phosphoglycerate.
8. Phosphoenolpyruvate formation prepares the molecule for which subsequent glycolytic reaction?
A. Conversion to glucose
B. Conversion to pyruvate
C. Conversion to fructose-6-phosphate
D. Conversion to glyceraldehyde-3-phosphate
Correct Answer:
Conversion to pyruvate
Explanation:
Phosphoenolpyruvate is the substrate for the next glycolytic reaction, in which it is converted to pyruvate.
9. Which pair correctly represents the substrate and product of enolase in glycolysis?
A. 2-phosphoglycerate and phosphoenolpyruvate
B. Glucose and glucose-6-phosphate
C. Pyruvate and lactate
D. Fructose-6-phosphate and fructose-1,6-bisphosphate
Correct Answer:
2-phosphoglycerate and phosphoenolpyruvate
Explanation:
Enolase converts 2-phosphoglycerate into phosphoenolpyruvate during glycolysis.
10. Why is phosphoenolpyruvate considered a high-energy glycolytic intermediate?
A. It contains a high-energy phosphate bond
B. It contains two sugar molecules
C. It is formed by adding ATP to glucose
D. It releases carbon dioxide during formation
Correct Answer:
It contains a high-energy phosphate bond
Explanation:
Phosphoenolpyruvate contains a high-energy phosphate bond, which allows it to participate in ATP formation in the next step of glycolysis.
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